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Derivative of Trigonometric Functions with Exam Style Problem MCV4U

Duration: 16:48Views: 194Likes: 23Date Created: Apr, 2022

Channel: Anil Kumar

Category: Education

Tags: math contestinverse functionsdifferentiationtrig derivativestrigonometric functionsap mathanil kumarderivativeaan learning centrecalculusanil kumar mathsurface areaderivativescollege algebraderivative of inverse functionsiit jeeepre calculus trigonometryibgrade 11calc 2gcsegrade 12igcseinversedifferential calculusinverse trigonometric functionssatgmatiit jeedifferentiate trig funtionsap calculus abmathib math sl

Description: Derivative of Inverse Functions: youtube.com/watch?v=OP0I_2L5Aqw&list=PLJ-ma5dJyAqoKK_KLugxDKtJjM7ipHQyv Inverse Trigonometric Functions: youtube.com/watch?v=aY7_e1wYbfY&list=PLJ-ma5dJyAqpObJ5rkt3y3R88WNAj7Qyx #InverseFunctions #InverseDerivatives #Calculus Derivative of Inverse Functions: Inverse function has reciprocal slope at corresponding points. Prove (f^(-1) )'(x)=1/(f^' (f^(-1) (x)) ) Application Verify that f(x) has an inverse. Then use the function f and the given real number a to find (f^(-1) )^' (a) Q1. f(x)=2x^3+4, find (f^(-1) )^' (a),a=20 Q2. f(x)=x^5-x^3+2x (f^(-1) )^' (a),a=2

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